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Division with remainder (missing number)

Division with remainder (missing number)

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Remainder after division

The result of division is not always a nice and round number, e.g. $7÷3$. We know that three fits twice into 7. However, $3×2=6$. There is 1 still remaining. We call 1 in this case the remainder or left over after dividing (7 is dividend and 3 is divisor).

7 ÷ 3++

To calculate it you need to find the greatest multiple of the divisor which is still lower than the dividend and subtract it from dividend.

Example:

$$44÷5 $$
$$;→; 5×8=40 ;→; 44−40=4 $$

4 is remainder after division by 5:

$$ 44=5×8+bo4$$

We write this also as:

$$44÷5 = 8 ;R;4$$

The remainder after division must always be smaller than the divisor. For example, when dividing by 8, the remainder can be from 1 to 7. If the dividend is divisible without a remainder, the remainder is 0.

$$24÷8 = 3 ;R;0$$

When the dividend is smaller than the the divisor, the quotient is always 0 and the remainder is the dividend itself. For example, in the division $2 ÷ 5 $, the answer is 0 with remainder of 2, because 5 does not fit into 2 at all. 

$$2 ÷ 5 = 0 ;R;2$$

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