### Long division by a one-digit number without a remainder

Division of larger numbers is difficult, so we use written forms.

581

$$1752÷8=?$$

The dividend in our example it is 1752 and the divisor is 8. We begin by determining whether the first digit of the dividend (here 1) is greater than or equal to the divisor (here 8). If so, we can divide these numbers. In our case, the first digit of the dividend is smaller than the divisor, so we must also use the second digit in the dividend. So we count how many times 8 fits into 17. We write 2 in the result and calculate the remainder. We multiply the divisor and the result (2×8=16), write the number 16 under 17 and subtract (17−16=1). This remainder must be less than the divisor.

587

To the remainder (1) we write another digit (5). Since 15 fits 8 only once, we write 1 in the result. We multiply this result again by the divisor (8) and subtract from 15.

588

We subtract and write another digit (2) to the remainder 7. We know that 8 fits into 72 exactly nine times, so we write 9 in the result and the remainder is 0. The result of the whole operation is 219. In division, we call the result the **quotient.**

589

Take a look at another example: 12008÷8

575

Sometimes it happens that two zeroes occur in the calculation (in our case the remainder after division was 0 and next digit was 0 as well). In this case we write 0 in the quotient and continue with the next number.

577

If there occurs dividend smaller than divisor (during calculation in the example below there is 00 and 001), we write 0 in the quotient and continue with the next number.

603